because each finite

Abelian group is determined by its endomorphism semigroup in the class of all groups ([7], Theorem 4.

3 A(n, H) and B(n, H) are the subgroups of an additive

Abelian group G.

1) according to addition, they form a linearly ordered

Abelian group,

Like a free

abelian group a free group consists of words, but these behave as follows: (a) when deciding when two words are equal, we are not allowed to rearrange their letters and antiletters and we may only create or annihilate letter/antiletter pairs if they occupy adjacent positions (for example, ACC'B = ABD'D but ACBC' is not equal to CAC'B); (b) the product of two words is again obtained by juxtaposing them; (c) to obtain the inverse of a word we must not only replace each letter by the corresponding antiletter and vice versa but reverse their order (for example, the inverse of AB' is BA', not A 'B).

If Q is a medial quasigroup, then there exist an

Abelian group <Q, +, -, 0>, its commuting automorphisms [phi] and [psi], and an element c [member of] Q such that

From [2] and [5], (M, *) forms an

Abelian group with identity element [[mu].

v](y) for all y [member of] Y} and (FL(V,W), +) is an

abelian group.

Let G be an

Abelian group and let E be a Banach space.

d], and is also isomorphic to the free

Abelian group on d generators.

Let G be an

abelian group of order G and let H be a subgroup of order h.

e], for e [member of] ob(G), an

abelian group, then A is maximal commutative in A [[?

Harinath, On the Cayley graph of an

abelian group, Proceedings of National Workshop on Graph Theory and its Applications, Manonmaniam Sundarnar University, Tirunelveli, February 21-27, 1996.