Cubic Equation(redirected from Irreducible Case)
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cubic equation[′kyü·bik i′kwā·zhən]
an algebraic equation of the third degree. The general form of a cubic equation is
ax3 + bx2 + cx + d = 0
where a ≠ 0. By replacing x in this equation by a new unknown y related to x by x = y − b/3a, a cubic equation can be reduced to the simpler (canonical) form
y3 + py + q = 0
p = b2/3a2 = c/a
q = 2b2/27a3 − bc/3a2 + da
The solution of this equation can be found using Cardan’s formula
If the coefficients of a cubic equation are real, then the nature of its roots depends on the sign of the radicand q2/4 + p/27 in Cardan’s formula. If q2/4 + p3/4 + p3/27 > 0, then the cubic equation has three different roots, one real and two complex conjugates. If q2/4 + p327 = 0, then all three roots are real, two of them being equal. If q2/4 + p3/27 > 0, then the three roots are real and different. The expression q2/4 + p3/27 differs by a constant factor from the discriminant of a cubic equation D = −4p3 − 27q2.
REFERENCESKurosh, A. G. Kurs vysshei algebry, 9th ed. Moscow, 1968.
Entsiklopediia elementarnoi matematiki, book 2. [Edited by P. S. Aleksandrov (et al.).] Moscow-Leningrad, 1951.